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Acceleration due to gravity on moon is 1/6 of the acceleration due to gravity on earth. If the ratio of densities of earth (ρm) is (ρeρm) = 5/3 then radius of moon
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SOLVED: (a) Calculate the magnitude of the acceleration due to gravity on the surface of Earth due to the Moon. (b) Calculate the magnitude of the acceleration due to gravity at Earth
SOLVED: Calculate the acceleration due to gravity at Earth due to the Moon; 3.33x10-5 m/s^2 You are correct. Previous Tries Your receipt no. is 157-1560 Calculate the acceleration due to gravity at
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The acceleration due to gravity on the surface of moon is 1.7 m s ^-2 . What is the time period of a simple pendulum on the surface of moon if its
If the acceleration due to gravity g at the earth's surface is 9.8 ms^-2 , mass of the earth 80 times that of moon and radius of the earth 4 times that
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![Mass of moon is 7.34 × 10^22kg . If the acceleration due to gravity on the moon is 1.4 ms^-2 , the radius of the moon is [G = 6.667 × 10^-11N m^2 kg^-2]](https://dwes9vv9u0550.cloudfront.net/images/12293749/eb09e220-5181-4442-82f4-31853c785512.jpg "Mass of moon is 7.34 × 10^22kg . If the acceleration due to gravity on the moon is 1.4 ms^-2 , the radius of the moon is [G = 6.667 × 10^-11N m^2 kg^-2]")